This is a blogging site especially for my dear students in PYSS Class 303 (2008). Welcome to this site and post all your difficult questions here for the smart people to answer!
We learn that diamonds sparkle as light entering the diamond is totally internally reflected many times before it exits the diamond. However, if you dip a diamond in water it loses its sparkle. Why is this so? - Prashaanth
what i think the answer to the Prashaanth's question is that..
let say the case in the air.. from the eqn, n¹sinθ¹=n²sinθ² (1)sinθ¹=(2.40)sin90º ※critical angle is 24.6º
let say the case in the water.. from the same eqn, n¹sinθ¹=n²sinθ² (1.33)sinθ¹=(2.40)sin90º ※critical angle is 33.7º
my answer only applies when the angle of incidence is greater than the critical angle..
Angle ,c is greater in water thus when the light rays enter the diamond the angle of incidence and reflection will be greater and thus the light rays will exist the diamond faster in water..
12 comments:
nobody as i guessed...
will you give me extra marks
if i post some very difficult
questions that i got from korean
assignment book? it has been a long
time since i studied it.
Please leave your name to identify yourself.
Mr Chua
i got. it is just that it is in korean.
jee soo lar i am
Put in English and then others can reply.
why you all so lame one korean also wanna put...
sometimes when i was having a high fever.. i felt that my hearing is soften(hard of hearing).. what causes this? is it because of the heat? or?
because i made google id in korea...
i am jee soo
Johan
Good question, got something to do with a tube again....
Anyone wants to find the answer?
Mr chua is that tube called auditory/eustachian/pharyngotympanic tube .. hehe that tube got lots of names >.>
We learn that diamonds sparkle as light entering the diamond is totally internally reflected many times before it exits the diamond. However, if you dip a diamond in water it loses its sparkle. Why is this so? - Prashaanth
what i think the answer to the Prashaanth's question is that..
let say the case in the air..
from the eqn, n¹sinθ¹=n²sinθ²
(1)sinθ¹=(2.40)sin90º
※critical angle is 24.6º
let say the case in the water..
from the same eqn, n¹sinθ¹=n²sinθ²
(1.33)sinθ¹=(2.40)sin90º
※critical angle is 33.7º
my answer only applies when the angle of incidence is greater than the critical angle..
Angle ,c is greater in water thus
when the light rays enter the diamond the angle of incidence and reflection will be greater and thus the light rays will exist the diamond faster in water..
this is just what i think.. try..
What gives rise to the "sparkle"?
perhaps start from there and deduce logically.....
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